MATH SOLVE

4 months ago

Q:
# Please help me answer for 29, 30, 31 please

Accepted Solution

A:

Answer:29. [tex]f(10) = 0.0078[/tex]30. [tex]f(5)=40.5[/tex]31. [tex]f(2)=6[/tex]Step-by-step explanation:Question 29:Given:[tex]f(n)=4\times (\frac{1}{2})^{n-1}[/tex]Plug in 10 for n. This gives,[tex]f(10)=4\times (\frac{1}{2})^{10-1}\\f(10)=4\times (\frac{1}{2})^{9}=0.0078[/tex]Therefore, the tenth term is 0.0078.Question 30:Given:[tex]f(n)=\frac{1}{2}\times 3^{n-1}[/tex]Plug in 5 for n. This gives,[tex]f(5)=\frac{1}{2}\times 3^{5-1}=\frac{1}{2}\times 3^4=\frac{1}{2}\times 81=40.5[/tex]Therefore, the fifth term is 40.5.Question 31:Given:[tex]f(1)=2, f(n)=f(n-1)+4[/tex]Plug in 2 for n. This gives,[tex]f(2)=f(1) + 4\\f(2)=2+4=6[/tex]Therefore, the second term is 6.